2x^2+19=4x^2-13

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Solution for 2x^2+19=4x^2-13 equation: 


Simplifying
2x2 + 19 = 4x2 + -13

Reorder the terms:
19 + 2x2 = 4x2 + -13

Reorder the terms:
19 + 2x2 = -13 + 4x2

Solving
19 + 2x2 = -13 + 4x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x2' to each side of the equation.
19 + 2x2 + -4x2 = -13 + 4x2 + -4x2

Combine like terms: 2x2 + -4x2 = -2x2
19 + -2x2 = -13 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
19 + -2x2 = -13 + 0
19 + -2x2 = -13

Add '-19' to each side of the equation.
19 + -19 + -2x2 = -13 + -19

Combine like terms: 19 + -19 = 0
0 + -2x2 = -13 + -19
-2x2 = -13 + -19

Combine like terms: -13 + -19 = -32
-2x2 = -32

Divide each side by '-2'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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